Factoring Help - Example Problems
In this article let me help you on factoring help with the help of following example.
Example: 1
Solve the following quadratic function f(x) = x2 + 15x + 54 = 0, with the help of factoring method.
Solution:
Let us first split the middle term +15x as 9x+ 6x
[Because (9x) × (6x) = 54x2 and 9x+6x = 15x].
So,
f (x) = x2 +9x +6x + 54
f (x) = x (x + 9) +6 (x +9)
f (x) = (x + 9)(x+ 6)
Now, f(x) = x2 + 15x + 54 = 0 can be rewritten as (x + 9)(x+ 6) = 0. This could also help us with exponential graph
So, the values of x for which x2 + 15x + 54 = 0 are the same for which (x + 9) (x+ 6) = 0. This could also help us on circle area
That is either (x + 9) = 0 or (x+ 6) = 0
Now, x +9 = 0 gives
x = -9
x + 6 = 0 gives x = -6
In this article let me help you on factoring help with the help of following example.
Example: 1
Solve the following quadratic function f(x) = x2 + 15x + 54 = 0, with the help of factoring method.
Solution:
Let us first split the middle term +15x as 9x+ 6x
[Because (9x) × (6x) = 54x2 and 9x+6x = 15x].
So,
f (x) = x2 +9x +6x + 54
f (x) = x (x + 9) +6 (x +9)
f (x) = (x + 9)(x+ 6)
Now, f(x) = x2 + 15x + 54 = 0 can be rewritten as (x + 9)(x+ 6) = 0. This could also help us with exponential graph
So, the values of x for which x2 + 15x + 54 = 0 are the same for which (x + 9) (x+ 6) = 0. This could also help us on circle area
That is either (x + 9) = 0 or (x+ 6) = 0
Now, x +9 = 0 gives
x = -9
x + 6 = 0 gives x = -6
